The Slope of The Slope: Second Derivatives
The second derivative measures a function's rate of curvature change, obtained by differentiating the first derivative. It's pivotal in determining concavity, inflection points, and optimizing real-world scenarios like motion dynamics.

The second derivatives create their own graph, which is distinct from the original function’s graph. This graph, often called the “second derivative graph” or “concavity graph,” visually represents the rate at which the slope of the original function changes. It helps in understanding the curvature behavior of the original function, indicating where it’s concave up or down, and locating any inflection points where the concavity changes.
Since you are already equipped with the tools required to solve the problems involving the second derivative,
let’s dive into problems:
\( \text{Find the first and second derivatives of } f(x) = x \sin x. \)
\( u = x, \ u’ = 1 \)
\( v = \sin x, \ v’ = \cos x \)
\( f'(x) = 1 \cdot \sin x + x \cdot \cos x \)
\( f'(x) = \sin x + x \cos x \)
\( (\sin x)’ = \cos x \)
\( (x \cos x)’ = 1 \cdot \cos x + x \cdot (-\sin x) \)
\( (x \cos x)’ = \cos x – x \sin x \)
\( f”(x) = \cos x + \cos x – x \sin x \)
\( f”(x) = 2\cos x – x \sin x \)
And that’s the second derivative of \( xsin x \)
Related to This Article
More math articles
- The Grocery Store Challenge: How to Use Unit Rates to Solve Word Problems
- 6th Grade Common Core Math FREE Sample Practice Questions
- How to Find Modulus (Absolute Value) and Argument (Angle) of Complex Numbers?
- Word Problems Involving Money
- How to Find the Perimeter of Polygons? (+FREE Worksheet!)
- 8 Useful Tips on Learning Mathematics Effectively
- Best Laptops For Online Math Teachers
- Pre-Algebra Worksheets: FREE & Printable (Updated for 2024)
- Unlock the Answers: “GED Math for Beginners” Solution Manual
- 10 Most Common 4th Grade IAR Math Questions
What people say about "The Slope of The Slope: Second Derivatives - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.