6th Grade SBAC Math Practice Test Questions
It may be difficult to pass the 6th Grade SBAC Math test, but we will make it easy for your student by providing the 6th Grade SBAC Math practice test questions. After a lot of research, our experts have collected 10 of the best common 6th Grade SBAC Math test questions. Detailed and step-by-step solutions to each question also are provided at the end of the post to help your 6th Grade student identify areas of weakness.
Make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions students need to practice.
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10 Sample 6th Grade SBAC Math Practice Questions
1- What is the missing prime factor of number 420?
\(420=2^2×3^1×…\)
A. \(2^2×3^1×5^1×7^1\)
B. \(2^2×3^1×7^1×9^1\)
C. \(1^2×2^3×2^1×3^1\)
D. \(3^2×5^1×7^1×9^1\)
2- If the area of the following trapezoid is equal to \(A\), which equation represents \(x\)?
A. \( x = \frac{13}{A}\)
B. \( x = \frac{A}{13}\)
C. \( x=A+13\)
D. \( x=A-13\)
3- By what factor did the number below change from the first to the fourth number?
\(8, 104, 1352, 17576\)
A. 13
B. 96
C. 1456
D. 17568
4- 170 is equal to …
A. \( -20-(3×10)+(6×40)\)
B. \(((\frac{15}{8})×72 )+ (\frac{125}{5}) \)
C. \(((\frac{30}{4} + \frac{15}{2})×8) – \frac{11}{2} + \frac{222}{4}\)
D. \(\frac{481}{6} + \frac{121}{3}+50\)
5- The distance between the two cities is 3,768 feet. What is the distance between the two cities in yards?
A. 1,256 yd
B. 11,304 yd
C. 45,216 yd
D. 3,768 yd
6- Mr. Jones saves $3,400 out of his monthly family income of $74,800. What fractional part of his income does Mr. Jones save?
A. \(\frac{1}{22}\)
B. \(\frac{1}{11}\)
C. \(\frac{3}{25}\)
D. \(\frac{2}{15}\)
7- What is the lowest common multiple of 12 and 20?
A. 60
B. 40
C. 20
D. 12
8- Based on the table below, which expression represents any value of f in term of its corresponding value of \(x\)?
A. \(f=2x-\frac{3}{10}\)
B. \(f=x+\frac{3}{10}\)
C. \(f=2x+2 \frac{2}{5}\)
D. \(2x+\frac{3}{10}\)
9- 96 kg \(=\)… ?
A. 96 mg
B. 9,600 mg
C. 960,000 mg
D. 96,000,000 mg
10- Calculate the approximate area of the following circle? (the diameter is 25)
A. 78
B. 491
C. 157
D. 1963
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Answers:
1- A
\(420=2^2×3^1×5^1×7^1\)
2- B
The area of the trapezoid is: area= \(\frac{(base 1+base 2)}{2})×height= ((\frac{10 + 16}{2})x = A\)
\( →13x = A→x = \frac{A}{13}\)
3- A
\(\frac{104}{8}=13, \frac{1352}{104}=13, \frac{17576}{1352}=13\)
Therefore, the factor is 13
4- C
Simplify each option provided.
\( A. -20-(3×10)+(6×40)=-20-30+240=190\)
\( B. (\frac{15}{8})×72 + (\frac{125}{5}) =135+25=160\)
\(C. ((\frac{30}{4} + \frac{15}{2})×8) – \frac{11}{2} + \frac{222}{4} = ((\frac{30 + 30}{4})×8)- \frac{11}{2}+ \frac{111}{2}=(\frac{60}{4})×8) + \frac{100}{2}= 120 + 50 = 170\)this is the answer
\(D. \frac{481}{6} + \frac{121}{3}+50= \frac{481+242}{6}+50=120.5+50=170.5\)
5- A
1 yard \(= \)3 feet
Therefore, \(3,768 ft × \frac{1 \space yd }{3 \space ft}=1,256 \space yd\)
6- A
3,400 out of 74,800 equals to \(\frac{3,400}{74,800}=\frac{17}{374}=\frac{1}{22}\)
7- A
Prime factorizing of \(20=2×2×5\)
Prime factorizing of \(12=2×2×3\)
LCM\(=2×2×3×5=60\)
8- C
Plug in the value of \(x\) into the function f. First, plug in 3.1 for \(x\).
\(A. f=2x-\frac{3}{10}=2(3.1)-\frac{3}{10}=5.9≠8.6\)
\(B. f=x+\frac{3}{10}=3.1+\frac{3}{10}=3.4≠10.8\)
\(C. f=2x+2 \frac{2}{5}=2(3.1)+2 \frac{2}{5}=6.2+2.4=8.6 \)
This is correct!
Plug in other values of \(x. x=4.2\)
\(f=2x+2\frac{2}{5} =2(4.2)+2.4=10.8 \)
This one is also correct.
\(x=5.9\)
\(f=2x+2 \frac{2}{5}=2(5.9)+2.4=14.2 \)
This one works too!
\(D. 2x+\frac{3}{10}=2(3.1)+\frac{3}{10}=6.5≠8.6\)
9- D
1 kg\(=\) 1000 g and 1 g \(=\) 1000 mg
96 kg\(=\) 96 \(×\) 1000 g \(=\)96 \(×\) 1000 \(×\) 1000 \(=\)96,000,000 mg
10- B
The diameter of a circle is twice the radius. Radius of the circle is \(\frac{25}{2}\).
Area of a circle = \(πr^2=π(\frac{25}{2})^2=156.25π=156.25×3.14=490.625≅491\)
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