How to Understanding Onto (Surjective) Functions

Step-by-step Guide to Understanding Onto (Surjective) Functions

Here is a step-by-step guide to understanding onto (surjective) functions:

Step 1: Understand the Definitions

• Function: A function is a relation between two sets, the domain and the codomain, such that each element of the domain is related to exactly one element of the codomain.
• Domain: The set of all possible input values.
• Codomain: The set of all possible output values.
• Onto (Surjective) Function: A function \(f\): \(A→B\) is said to be onto (or surjective) if every element of codomain \(B\) has a pre-image in the domain \(A\).

Step 2: Visualize with a Diagram

Drawing a mapping diagram can be a great way to understand how elements from the domain map to the codomain.

Step 3: Understand the Condition for Onto

For a function \(f\): \(A→B\) to be onto, for every element \(b∈B\), there must exist at least one element \(a∈A\) such that \(f(a)=b\).

Step 4: Use Algebraic Methods

For algebraic functions, you can prove surjectivity by:

1. Taking a generic element \(b\) from the codomain.
2. Trying to express an element \(a\) from the domain in terms of \(b\) such that \(f(a)=b\).

For example, for the function \(f(x)=2x+3\), if you can find an inverse function that gives you a value in the domain for every element in the codomain, then \(f(x)\) is onto.

Step 5: Work with Examples

To get comfortable with the concept, test various functions for surjectivity:

1. Onto Function: \(f\): \(R→R\) defined by \(f(x)=x+3\). For every real number \(y\), there’s a real number \(x\) such that \(f(x)=y\).
2. Not Onto: \(f\): \(R→R\) defined by \(f(x)=x^2\). It’s not onto in the real numbers because, for negative values in the codomain, there’s no real number \(x\) such that \(f(x)=y\).

Step 6: Counterexamples

When claiming a function is not onto, often a counterexample is provided. For instance, with the function \(f(x)=x^2\), the number \(-1\) from the codomain has no pre-image in the domain, so the function isn’t onto.

Step 7: Understand the Importance

Understanding onto functions is essential in various branches of mathematics, including algebra and topology. It is also a fundamental concept in defining bijective functions, which are both injective (one-to-one) and surjective (onto).

By following this guide, working through examples, and visualizing the concept with diagrams, you can gain a robust understanding of onto (surjective) functions.

Examples:

Example 1:

Is the function \(f(x)=x+2\) from the set of real numbers to the set of real numbers an onto function?

Solution:

Given: Function \(f\): \(R→R\) defined by \(f(x)=x+2\)

To check if the function is onto: For the function to be onto, for every element \(y\) in the codomain, there should exist an element \(x\) in the domain such that \(f(x)=y\).

1. Let’s take a generic element \(y\) from the codomain \(R\).
2. We need to express \(x\) in terms of \(y\) such that \(f(x)=y\).

From the function definition: \(f(x)=x+2=y\)

Now, solving for \(x\): \(x=y−2\)

Since \(y\) is any real number, \(y−2\) will also be a real number. This means that for every real number \(y\), there exists an \(x\) in the domain of real numbers such that \(f(x)=y\).

The function \(f(x)=x+2\) from the set of real numbers to the set of real numbers is an onto function because it covers every real number in its codomain.

Example 2:

Is the function \(f(x)=3x\) from the set of real numbers to the set of real numbers an onto function?

Solution:

Given: Function \(f\): \(R→R\) defined by \(f(x)=3x\)

To determine if the function is onto: For the function to be onto, for every element \(y\) in the codomain, there should exist an element \(x\) in the domain such that \(f(x)=y\).

1. Let’s take a generic element \(y\) from the codomain \(R\).
2. We aim to express \(x\) in terms of \(y\) so that \(f(x)=y\).

From the function definition: \(f(x)=3x=y\)

Now, solving for \(x\): \(\frac{y}{3}\)

Since \(y\) is any real number, \(\frac{y}{3}\)​ will also be a real number. This indicates that for every real number \(y\), there’s an \(x\) in the domain of real numbers such that \(f(x)=y\).

The function \(f(x)=3x\) from the set of real numbers to the set of real numbers is an onto function because it can generate every real number in its codomain.