How to Find the Focus, Vertex, and Directrix of a Parabola?
You can easily find the focus, vertex, and directrix from the standard form of a parabola.
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“A parabola consists of three parts: the vertex, focus, and directrix. The vertex represents the point where the curve reaches its maximum or minimum value, while the focus is a fixed point located inside the parabola. The directrix lies outside the curve and runs parallel to its axis. If these geometric concepts seem tricky at first, you can solve math at Edubrain to get step-by-step guidance and interactive explanations that make the process of learning much easier.
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Step-by-Step Guide to Finding the Focus, Vertex, and Directrix of a Parabola
- For a Parabola in the form \(y=ax^2+bx+c\):
Vertex: \((\frac{-b}{2a}, \frac{4ac-b^2}{4a})\), Focus: \((\frac{-b}{2a}, \frac{4ac-b^2+1}{4a})\), Direcrix: \(y=c-(b^2+1)4a\).
Finding the Focus, Vertex, and Directrix of a parabola – Example 1:
Find the vertex and focus of this parabola: \(y=3x^2+6x\)
Solution:
The Parabola given parameters are: \(a=3, b=6, c=0\)
Substitute the values in vertex formula: \((\frac{-b}{2a}, \frac{4ac-b^2}{4a})=(\frac{-6}{2(3)}, \frac{4(3)(0)-6^2}{4(3)})\)
Therefore, the vertex of the parabola is \((-1, 3)\).
To find the focus of the parabola, substitute the values in the focus formula: \((\frac{-b}{2a}, \frac{4ac-b^2+1}{4a})=(\frac{-6}{2(3)}, \frac{4(3)(0)-6^2+1}{4(3)})\)
Focus of parabola is \((-1, \frac{-35}{12})\).
Exercises for Finding the Focus, Vertex, and Directrix of Parabola
Find the vertex and focus of each parabola.
- \(\color{blue}{(y-2)^2=3(x-5)^2}\)
- \(\color{blue}{y=4x^2+x-1}\)
- \(\color{blue}{y=x^2+2x+3}\)
- \(\color{blue}{x=y^2-4y}\)
- \(\color{blue}{Vertex: (5, 2),}\) \(\color{blue}{focus: (5, \frac{25}{12})}\)
- \(\color{blue}{Vertex: (\frac{-1}{8}, \frac{-17}{16}), focus: (\frac{-1}{8}, -1)}\)
- \(\color{blue}{Vertex: (-1, 2), focus: (-1, \frac{9}{4})}\)
- \(\color{blue}{Vertex: (-4, 2), focus: (\frac{-15}{4}, 2)}\)
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