How to Find the Center and the Radius of Circles? (+FREE Worksheet!)
To find the center and radius of a circle from its equation, you need to find the equation of the circle in is the center-radius form.
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Rules for Finding the Center and the Radius of Circles
To find the center and the radius of a circle using the equation of the circle:
- Write the equation of the circle in standard form: \((x- h)^2+( y-k)^2= r^2\),
- The center of the circle is at \(h,k\), and its radius is \(r\).
![](https://www.effortlessmath.com/wp-content/uploads/2021/04/d1.png)
Find the Center and the Radius of Circles – Example 1:
Identify the center and the radius of each circle.
\(x^2+ y^2-4x+3=0\)
Solution:
\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).
Rewrite \(x^2+ y^2-4x+3=0\) in the standard form:
\(x^2+ y^2-4x+3=0→(x-2)^2+(y-0)^2=1^2 \)
Then, the center is at: \((2,0)\) and \(r=1\)
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Find the Center and the Radius of Circles – Example 2:
Identify the center and the radius of each circle.
\(8x+x^2+10y=8- y^2\)
Solution:
\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).
Rewrite the equation in standard form:
\(8x+x^2+10y=8- y^2→(x-(-4))^2+(y-(-5))^2=7^2 \)
Then, the center is at \((-4,-5)\) and the \(r=7\).
Find the Center and the Radius of Circles – Example 3:
Identify the center and radius.
\(8x+x^2-2y=8- y^2 \)
Solution:
\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).
Rewrite \(8x+x^2-2y=8- y^2\) in the standard form:
\((x-(-4))^2+(y-1)^2=5^2\)
Then, the center is at \((-4,1)\) and \(r=5\)
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