Full-Length SSAT Upper Level Practice Test-Answers and Explanations

40- Choice E is correct
The capacity of a red box is \(50\%\) bigger than the capacity of a blue box and it can hold 45 books. Therefore, we want to find a number that \(30\%\) is bigger than that number is 60. Let \(x\) be that number. Then:
\(1.50×x=45\), Divide both sides of the equation by 1. 5. Then:
\(x=\frac{45}{1.50}=30\)

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41- Choice C is correct
Since E is the midpoint of AB, then the area of all triangles DAE, DEF, CFE, and CBE are equal.
Let \(x\) be the area of one of the triangles than \(4x=200→x=50\)
The area of DEC \(=2x=2(50)=100\)

42- Choice D is correct
Amount of available petrol in tank: \(48.3-7.96-18.21+16.47=38.6\) liters

43- Choice E is correct
We have two equations and three unknown variables, therefore \(x\) cannot be obtained.

44- Choice A is correct
\(5y+5<51→5y<51-6→5y<45→y<9\)
The only choice that is less than 8 is E.

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45- Choice C is correct
Perimeter of figure A is: \(2πr=2π \frac{14}{2}=14π=14×3=42 \)
Area of figure B is:\( 15×7=105\), Average \(=\frac{42+105}{2}=\frac{150}{2}=75\)

46- Choice C is correct
The angles on a straight line add up to 180 degrees. Let’s review the choices provided:
A. \(y=15→ x+25+y+2x+y=25+25+15+2(25)+15=130≠180\)
B. \(y=25→ x+25+y+2x+y=25+25+25+2(25)+25=150≠180 \)
C. \(y=40→ x+25+y+2x+y=25+25+40+2(25)+40=180=180 \)
D. \(y=45→ x+25+y+2x+y=25+25+45+2(25)+45=190≠180 \)
E. \(y=55→ x+25+y+2x+y=25+25+55+2(25)+55=210≠180\)

47- Choice E is correct
Let’s review the choices provided:
A. \(x=\frac{1}{2}→ \frac{2}{7}+\frac{1}{2}=\frac{4+7}{14}=\frac{11}{14}≅0.78<3 \)
B. \(x=\frac{3}{5}→ \frac{2}{7}+\frac{3}{5}=\frac{10+21}{35}=\frac{31}{35}≅0.88<3 \)
C. \(x=\frac{4}{5}→ \frac{2}{7}+\frac{4}{5}=\frac{10+28}{35}=\frac{38}{35}≅1.085<3 \)
D. \(x=\frac{4}{3}→ \frac{2}{7}+\frac{4}{3}=\frac{6+28}{21}=\frac{34}{21}≅1.61<3 \)
E. \(x=\frac{10}{3}→ \frac{2}{7}+\frac{10}{3}=\frac{6+70}{21}=\frac{76}{21}≅3.61>3 \)
Only choice E be is correct.

48- Choice B is correct
Set of numbers that are not composite between 8 and 17: A= {11, 13, 17}
Probability = \(\frac{number of desired outcomes}{number of total outcomes}=\frac{ 3}{10}\)

49- Choice C is correct
\(432÷4=\frac{432}{4}=\frac{400+30+2}{4}=\frac{400}{4}+\frac{30}{4}+\frac{2}{4}\)

50- Choice E is correct
\(\frac{4}{6}×36=\frac{144}{6}=24\)

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