FREE ISEE Middle Level Math Practice Test

FREE ISEE Middle Level Math Practice Test

B. 314 cm\(^2\)

C. 63 cm\(^2\)

D. 126 cm\(^2\)

9- If \(150\%\) of a number is 75, then what is the \(90\%\) of that number?

A. 45

B. 50

C. 70

D. 85

10- What is the missing term in the given numbers?
2, 3, 5, 8, 12, 17, 23, _, 38

A. 24

B. 26

C. 28

D. 30

11- From last year, the price of gasoline has increased from $1.25 per gallon to $1.75 per gallon. The new price is what percent of the original price?

A. \(72 \%\)

B. \(120 \%\)

C. \(140 \%\)

D. \(160 \%\)

12- 195 minutes = …?

A. 3.25 Hours

B. 2.16 Hours

C. 2 Hours

D. 0.3 Hours

13- If a gas tank can hold 25 gallons, how many gallons does it contain when it is \(\frac{2}{5}\) full?

A. 50

B. 125

C. 62.5

D. 10

14- Which of the following is not a prime number?

A. 103

B. 101

C. 97

D. 57

15- What is the perimeter of a square that has an area of 64 square inches?

A. 144 inches

B. 64 inches

C. 32 inches

D. 56 inches

16- Which of the following angles can represent the three angles of an isosceles right triangle?

A. \(10^\circ, 80^\circ, 90^\circ\)

B. \(50^\circ, 50^\circ, 80^\circ\)

C. \(60^\circ, 60^\circ, 60^\circ\)

D. \(45^\circ, 45^\circ, 90^\circ\)

17- In the following rectangle, which statement is true?

A. AB is parallel to BC.

B. The sum of all the angles equals 180\(^\circ\).

C. Length of AB equal to length DC.

D. AB is perpendicular to DC.

18- \(7^4=?\)

A. \(7+4\)

B. \(7×4\)

C. \(7+7+7+7\)

D. \(7×7×7×7\)

19- A football team had $20,000 to spend on supplies. The team spent $14,000 on new balls. New sports shoes cost $120 each. Which of the following inequalities represents how many new shoes the team can purchase?

A. \(120x+14,000 ≤20,000 \)

B. \(120x+14,000 ≥20,000\)

C. \(14,000x+120 ≤20,000\)

D. \(14,000x+12,0 ≥20,000\)

20- The red box is \(30\%\) greater than the blue box. If 30 books exist in the red box, how many books exist in the blue box?

A. 9

B. 15

C. 21

D. 30

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Answers:

1- D
\(12.124÷0.002=\frac{\frac{12124}{1000}}{\frac{2}{1000}}=\frac{12124}{2}=6062\)

2- A
\(10+4(x+5-5x)=10+4(-4x+5)=30→10-16x+20=30→-16x+30=30→-16x=0→x=0\)

3- B
\(15\% \space \)of \(\space 180=\frac{15}{100}×180=27\)
Let \(x\) be the number then, \(x = 27 + 12 = 39\)

4- B
\(\frac{2}{3}×90=60\)

5- A
\(3(\frac{1}{3} – \frac{1}{6}) +4=3(\frac{12-1}{6}) +4\)
\(\frac{3}{6}+4=\frac{1}{2}+ 4= \frac{9}{2}=4.5\)

6- B
Prime factorizing of \(70=2×5×7\)
Prime factorizing of \(66=2×3×11\)
GCF\(=2\)

7- C
\(\frac{1}{2}=0.5\)
\(\frac{7}{9}=0.77\)
\(65\%=0.65\)

8- B
Area\(=πr^2=π×(\frac{20}{2})^2=100π=100×3.14=314\)

9- A
First, find the number.
Let \(x\) be the number. Write the equation and solve for \(x\).
\(150\%\) of a number is 75, then:
\(1.5×x=75 ⇒ x=75÷1.5=50\)
\(90\%\) of 50 is:
\(0.9 × 50 = 45\)

10- D
Find the difference of each pair of numbers:
2, 3, 5, 8, 12, 17, 23, _, 38
The difference of 2 and 3 is 1, 3 and 5 is 2, 5 and 8 is 3, 8 and 12 is 4, 12 and 17 is 5, 17 and 23 is 6, 23 and the next number should be 7.
The number is \(23 + 7 = 30\)

11- C
The question is this: 1.75 is what percent of 1.25?
Use the percent formula:
Part \(= \frac{percent}{100}×\) whole
\(1.75= \frac{percent}{100}× 1.25 ⇒ 1.75 =\frac{percent ×1.25}{100}⇒175 =\) percent \(×1.25 ⇒\) percent \(=\frac{175}{1.25}=140\)

12- A
60 minutes = 1Hours\(→(\frac{195}{60}) = 3.25\) Hours

13- D
\(\frac{2}{5}×25=\frac{50}{5}=10\)

14- D
57 is not a prime number; it is divided by 3

15- C
The area of the square is 64 square inches. Therefore, the side of the square is the square root of the area.
\(\sqrt{64}=8\) inches
Four times the size of the square is the perimeter:
\(4 × 8 = 32\) inches

16- D
\(2α+90^\circ=180^\circ→2α=90^\circ→α=45^\circ\)

17- C
In a rectangle sides that face to face, each other are equal.

18- D
\(7^4=7×7×7×7\)

19- A
Let \(x\) be the number of shoes the team can purchase. Therefore, the team can purchase \(120 x\).
The team had $20,000 and spent $14000. Now the team can spend on new shoes $6000 at most.
Now, write the inequality:
\(120x+14,000 ≤20,000\)

20- C
Number of books in \(30\%\) of red box\(= \frac{30}{100}×30=9→30-9=21\)

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