How to Evaluate Logarithm? (+FREE Worksheet!)
Since learning the rules of logarithms is essential for evaluating logarithms, this blog post will teach you some logarithmic rules for the convenience of your work in evaluating logarithms.

Related Topics
- How to Solve Natural Logarithms
- How to Use Properties of Logarithms
- How to Solve Logarithmic Equations
Necessary Logarithms Rules
- Logarithm is another way of writing exponent. logby=x is equivalent to y=bx.
- Learn some logarithms rules: (a>0,a≠0,M>0,N>0, and k is a real number.)
Rule 1: logaM.N=logaM+logaN
Rule 2: logaMN=logaM−logaN
Rule 3: loga(M)k=klogaM
Rule 4: logaa=1
Rule 5:loga1=0
Rule 6: alogak=k
Examples
Evaluating Logarithm – Example 1:
Evaluate: log232
Solution:
Rewrite 32 in power base form: 32=25, then:
log232=log2(2)5
Use log rule:loga(M)k=k.logaM→log2(2)5=5log2(2)
Use log rule: loga(a)=1→log2(2)=1.
5log2(2)=5×1=5
Evaluating Logarithm – Example 2:
Evaluate: 3log5125
Solution:
Rewrite 125 in power base form: 125=53, then:
log5125=log5(5)3
Use log rule: loga(M)k=k.logaM→log5(5)3=3log5(5)
Use log rule: loga(a)=1→log5(5)=1.
3×3log5(5)=3×3=9
Evaluating Logarithm – Example 3:
Evaluate: log101000
Solution:
Rewrite 1000 in power base form: 1000=103, then:
log101000=log10(10)3
Use log rule:loga(M)k=k.logaM→log10(10)3=3log10(10)
Use log rule: loga(a)=1→log10(10)=1.
3log10(10)=3×1=3
Evaluating Logarithm – Example 4:
Evaluate: 5log381
Solution:
Rewrite 81 in power base form: 81=34, then:
log381=log3(3)4
Use log rule: loga(M)k=k.logaM→log3(3)4=4log3(3)
Use log rule: loga(a)=1→log3(3)=1.
5×4log3(3)=5×4=20
Exercises for Evaluating Logarithm
Evaluate Logarithm.
- 3log264
- 12log636
- 13log327
- log464
- log10001
- log620620

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