10 Most Common TASC Math Questions

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10 Sample TASC Math Practice Questions

1- If \(60\%\) of A is \(20\%\) of B, then B is what percent of A?

A. \(3\%\)

B. \(30\%\)

C. \(200\%\)

D. \(300\%\)

2- The price of a car was $20,000 in 2014, $15,000 in 2015 and $11,200in 2016. What is the rate of depreciation of the price of a car per year?

A. \(15\%\)

B. \(25\%\)

C. \(30\%\)

D. \(35\%\)

3- The width of a box is one-third of its length. The height of the box is one-third of its width. If the length of the box is 45 cm, what is the volume of the box?

A. 81 cm\(^3\)

B. 162 cm\(^3\)

C. 243 cm\(^3\)

D. 3,375 cm\(^3\)

4- How many possible outfit combinations come from six shirts, three slacks, and five ties?

A. 15

B. 18

C. 30

D. 90

5- A bank is offering \(4.5\%\) simple interest on a savings account. If you deposit $8,000, how much interest will you earn in five years?

A. $360

B. $720

C. $1,800

D. $3,600

6- What is the value of \(6^4 \)?

A. 216

B. 1,296

C. 7,776

D. 46,656

7- 15 is What percent of 20?

A. \(20\%\)

B. \(25\%\)

C. \(75\%\)

D. \(125\%\)

8- The perimeter of the trapezoid below is 56. What is its area?

A. 56 cm

B. 132 cm

C. 156 cm

D. 175 cm

9-In five successive hours, a car traveled 40 km,45 km,50 km,35 km, and 55 km. In the next five hours, it traveled with an average speed of 65 km per hour. Find the total distance the car traveled in 10 hours.

A. 425 km

B. 450 km

C. 550 km

D. 600 km

10- How long does a 420–miles trip take moving at 65 miles per hour (mph)?

A. 4 hours

B. 4 hours and 24 minutes

C. 6 hours and 24 minutes

D. 8 hours and 30 minutes

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Answers:

2- B
Use this formula: Percent of Change \(\frac{New \ Value-Old \ Value}{Old \ Value}×100\% \)
\(\frac{15000-20000}{20000}×100\%=-25\%\) and \(\frac{11200-15000}{15000}×100\%=-25\% \)

3- D
If the length of the box is 45, then the width of the box is one-third of it, 15, and the height of the box is 5 (one-third of the width). The volume of the box is:
V=lwh =(45)(15)(5)=3375

4- D
To find the number of possible outfit combinations, multiply number of options for each factor: \(6×3×5=90\)

5- C
Use simple interest formula: I=prt (I=interest,p=principal,r=rate,t=time)
I=(8,000)(0.045)(5)=1,800

6- B
\(6^4\)=6×6×6×6=1,296

7- C
\(x=\frac{15}{20}=0.75=75\% \)

8- C
The perimeter of the trapezoid is 56. Therefore, the missing side (height) is =56-18-12-14=12. Area of a trapezoid: \(A=\frac{1}{2 } h (b_{1}+b_{2})=\frac{1}{2}(12)(12+14)=156\)

9- C
Add the first 5 numbers. 40+45+50+35+55=225
To find the distance traveled in the next 5 hours, multiply the average by the number of hours.
Distance=Average×Rate = 65×5 =325
Add both numbers. 325+225=550

10- C
Use distance formula: Distance =Rate×time ⇒ 420=65×T, divide both sides by \(65. 420÷65=T ⇒ T=6.4\) hours. Change hours to minutes for the decimal part. 0.4 hours =0.4×60 =24 minutes.

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