10 Most Common SSAT Middle Level Math Questions

Preparing for the SSAT Middle-Level Math test? Want a preview of the most common mathematics questions on the SSAT Middle-Level Math test? If so, then you are in the right place.

The mathematics section of SSAT Middle Level can be a challenging area for many test-takers, but with enough patience, it can be easy and even enjoyable!

Preparing for the SSAT Middle-Level Math test can be a nerve-wracking experience. Learning more about what you’re going to see when you take the SSAT Middle Level can help to reduce those pre-test jitters. Here’s your chance to review the 10 most common SSAT Middle-Level Math questions to help you know what to expect and what to practice most. Try these 10 most common SSAT Middle-Level Math questions to hone your mathematical skills and to see if your math skills are up to date on what’s being asked on the exam or if you still need more practice.

Make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions you need to practice.

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10 Sample SSAT Middle-Level Math Practice Questions

1- The score of Emma was half as that of Ava and the score of Mia was twice that of Ava. If the score of Mia was 40, what is the score, Emma?

A. 10

B. 18

C. 20

D. 30

E. 32

2- Two-third of 9 is equal to \(\frac{2}{5}\) of what number?

A. 60

B. 20

C. 15

D. 30

E. 36

3- If three times a number added to 5 equals 32, what is the number?

A. 2

B. 4

C. 6

D. 9

E. 10

4- Solve for \(?: 4(?+1)=6(?−4)+20\)

A. 12

B. 6.5

C. 4

D. 2

E. 1

5- Karen is 9 years older than her sister Michelle, and Michelle is 4 years younger than her brother David. If the sum of their ages is 82, how old is Michelle?

A. 14

B. 23

C. 22

D. 25

E. 25

6- Two-kilogram apple and two-kilogram orange cost $26.4. If a one-kilogram apple costs $4.2 how much does one-kilogram orange cost?

A. $9

B. $6

C. $5.5

D. $5

E. $4.5

7- The average weight of 18 girls in a class is 50 kg and the average weight of 32 boys in the same class is 62 kg. What is the average weight of all the 50 students in that class?

A. 57.68

B. 61.68

C. 61.90

D. 62.20

E. 64.00

8- What is the value of \(?\) in this equation? \(6?+4=78\)

A. 4

B. 6

C. 9

D. 10

E. 12

9-When a number is subtracted from 32 and the difference is divided by that number, the result is 3. What is the value of the number?

A. 2

B. 4

C. 8

D. 12

E. 15

10- Which is the correct statement?

A. \(\frac{3}{4}>0.8\)

B. \(10\%=\frac{2}{5}\)

C. \(3<\frac{5}{2}\)

D. \(\frac{5}{6}>0.8\)

E. \(2.5\%=0.25\)

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Answers:

2- C
Let \(x\) be the number. Write the equation and solve for \(x\). \(\frac{2}{3} ×9= \frac{2}{5 } \).
\(x⇒\frac{2×9}{3}= \frac{2x}{5}\) , use cross multiplication to solve for \(x. 5×18=2x×3⇒90=6x⇒ x=15\)

3- D
Let \(x\) be the number. Then: \(3x+5=32\) Solve for \(x\): \(3x+5=32→3x=32-5=27→
x=27÷3=9\)

4- C
Simplify and solve for \(x\) in the equation. \(4(x+1)=6(x-4)+20, 4x+4= 6x-24+20, 4x+4=6x-4\). Subtract \(4x\) from both sides: \(4=2x-4\), Add 4 to both sides: \(8=2x, 4=x\)

5- B
Let’s write equations based on the information provided:
Michelle = Karen \(-9\),Michelle = David \(- 4\), Karen + Michelle + David =82
Karen \(- 9\)=Michelle ⇒ Karen = Michelle +9
Karen + Michelle + David = 82
Now, replace the ages of Karen and David with Michelle. Then:
Michelle +9+ Michelle + Michelle +4 =82
3× Michelle +13=82⇒ 3× Michelle = \(82-13\)
3× Michelle =69, Michelle=23

6- A
Let \(x\) be one-kilogram orange cost, then:\(2x+(2×4.2)=26.4→2x+8.4=26.4→
2x=26.4-8.4→2x=18→x=\frac{18}{2}=$9\)

7- A
average \(=\frac{sum \ of \ terms }{number \ of \ terms}\), The sum of the weight of all girls is: 18×50=900 kg, The sum of the weight of all boys is: 32×62=1,984 kg, The sum of the weight of all students is:
900+ 1,984=2,884 kg, Average \(=\frac{2,884}{50}=57.68\)

8- C
Solve for \(x\) in the equation. \(6(x+4)=78→6x+24=78→6x=78-24=54→
x=54÷6=9\)

9- C
Let \(x\) be the number. Write the equation and solve for \(x. (32-x)÷ x = 3\)
Multiply both sides by \(x. (32-x)= 3x\), then add \(x\) both sides. \(32=4x\), now divide both sides by \(4. x=8\)

10- E
Only option D is correct. \(\frac{5}{6}=0.83→0.8<\frac{5}{6}\)

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