10 Most Common 6th Grade IAR Math Questions
B. The measure of the sum of all the angles equals \(360^\circ\).
C. Length of AB equal to length DC.
D. AB is perpendicular to AC.
5- The area of a rectangular yard is \(90\) square meters. What is its width if its length is \(15\) meters?
A. \(10\) meters
B. \(8\) meters
C. \(6\) meters
D. \(4\) meters
6- Which statement about \(4\) multiplied by \(\frac{3}{5}\) must be true?
A. The product is between \(1\) and \(2\)
B. The product is greater than \(3\)
C. The product is equal to \(\frac{75}{31}\)
D. The product is between \(2\) and \(2.5\)
7- Which of the following lists shows the fractions in order from least to greatest?
\(\frac{3}{4}, \frac{2}{7}, \frac{3}{8}, \frac{5}{11}\)
A. \(\frac{3}{8}, \frac{2}{7}, \frac{3}{4}, \frac{5}{11}\)
B. \(\frac{2}{7}, \frac{5}{11}, \frac{3}{8}, \frac{3}{4}\)
C. \(\frac{2}{7}, \frac{3}{8}, \frac{5}{11}, \frac{3}{4}\)
D. \(\frac{3}{8}, \frac{2}{7}, \frac{5}{11}, \frac{3}{4}\)
8- A car costing \($300\) is discounted \(10\%\). Which of the following expressions can be used to find the selling price of the car?
A. \((300)(0.4)\)
B. \(300-(300×0.1)\)
C. \((300)(0.1)\)
D. \( 300-(300×0.9)\)
9- What is the missing price factor of the number \(420\)?
\(420=2^2×3^1×…\)
A. \(2^2×3^1×5^1×7^1\)
B. \(2^2×3^1×7^1×9^1\)
C. \(1^2×2^3×2^1×3^1\)
D. \(3^2×5^1×7^1×9^1\)
10- If the area of the following trapezoid is equal to \(A\), which equation represents \(x\)?
A. \(x = \frac{13}{A}\)
B. \(x = \frac{A}{13}\)
C. \( x=A+13\)
D. \( x=A-13\)
Best 6th Grade IAR Math Practice Resource
Common Core Math Exercise Book for Grade 6 Student Workbook and Two Realistic Common Core Math Tests
Answers:
1- C
The slope of the line is:
\(\frac{y_2-y_1}{x_2-x_1 }= \frac{8 – 4}{2 – 0}=\frac{4}{2}=2\)
The equation of a line can be written as:
\( y-y_0=m(x – x_0 )→y-4 = 2(x – 0)→y-4 = 2x→y = 2x + 4\)
2- D
Volume of a \(box = length × width × height = 6 × 7 × 9 = 378\)
3- B
\(Probability = \frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes}=\frac{15}{14+15+16+20}= \frac{15}{65}=\frac{3}{13}\)
4- D
In any rectangle, sides are not perpendicular to diagonals.
5- C
Let \(y\) be the width of the rectangle. Then; \(15×y=90→y=\frac{90}{15}=6\)
6- D
\( 4×\frac{3}{5}=\frac{12}{5}=2.4 \)
\( 2.4>2\)
\( 2.4<3\)
\( \frac{75}{31}=2.419≠2.4\)
\(2<2.4<2.5 \) This is the answer!
7- C
Let’s compare each fraction:
\(\frac{2}{7}< \frac{3}{8}< \frac{5}{11} < \frac{3}{4}\)
Only choice C provides the right order.
8- B
To find the discount, multiply the number (\(100\%\)\(-\) rate of discount)
Therefore; \(300(100\%-10\%)=300(1-0.1)=300-(300×0.1)\)
9- A
\(420=2^2×3^1×5^1×7^1\)
10- B
The area of the trapezoid is: area= \(\frac{(base 1+base 2)}{2}×height= (\frac{10 + 16}{2})x = A\)
\( →13x = A→x = \frac{A}{13}\)
Looking for the best resource to help you succeed on the Grade 6 IAR Math test?
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