Intelligent Math Puzzle – Challenge 89
This mind-blowing mathematics and critical thinking challenge is not for the faint at heart—or mind. Can you solve it?
![Intelligent Math Puzzle – Challenge 89](https://www.effortlessmath.com/wp-content/uploads/2020/04/Challenge-89-512x240.jpg)
Challenge:
![](https://www.effortlessmath.com/wp-content/uploads/2020/04/p.png)
In the figure above, A, B, and C represent different digits. What is the value of B + C?
A- 8
B- 11
C- 15
D- 17
E- 18
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![](https://www.effortlessmath.com/wp-content/uploads/2020/04/answer.png)
The correct answer is C.
In this problem, we can write a system of three equations and three variables.
Let’s review the equations.
A + B + C = 9 or 19
A + A + C = 5 or 15
A + A + A = 13 or 12
3A cannot be 13. Therefore, 3A = 12 ⇒ A = 4
We can also conclude that in the second equation:
A + A + C = 15 ⇒ 2A + C = 15 ⇒ C = 7
Or A + A + C = 16 (1 may added from the first column)
C = 6
Try different values for the first equation:
A + B + C = 9 or 19
If A = 4 and C = 6 ⇒ B = 9
If A = 4 and C = 7 ⇒ B = 8
B + C = 15
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