Geometry Puzzle – Challenge 71
This is a fun and engaging math puzzle to challenge even the smartest students and help them develop logic skills. For additional educational resources, . For additional educational resources
[include_netrun_products_block from-products="product/the-ultimate-middle-school-math-bundle/" product-list-class="bundle-products float-left" product-item-class="float-left" product-item-image-container-class="p-0 float-left" product-item-image-container-size="col-2" product-item-image-container-custom-style="" product-item-container-size="" product-item-add-to-cart-class="btn-accent btn-purchase-ajax" product-item-button-custom-url="{{url}}/?ajax-add-to-cart={{id}}" product-item-button-custom-url-if-not-salable="{{productUrl}} product-item-container-class="" product-item-element-order="image,title,purchase,price" product-item-title-size="" product-item-title-wrapper-size="col-10" product-item-title-tag="h3" product-item-title-class="mt-0" product-item-title-wrapper-class="float-left pr-0" product-item-price-size="" product-item-purchase-size="" product-item-purchase-wrapper-size="" product-item-price-wrapper-class="pr-0 float-left" product-item-price-wrapper-size="col-10" product-item-read-more-text="" product-item-add-to-cart-text="" product-item-add-to-cart-custom-attribute="title='Purchase this book with single click'" product-item-thumbnail-size="290-380" show-details="false" show-excerpt="false" paginate="false" lazy-load="true"]
Challenge:
The total weight of a box and the candies it contains is 12 pounds. After \(\frac{2}{3}\) of the candies are eaten, the box and the remaining candies weigh 5 pounds. What is the weight of the empty box in pounds?
A- \(\frac{2}{3}\)
B- 1
C- \(\frac{3}{2}\)
D- \(2\frac{1}{2}\)
E- 5
The Absolute Best Book to challenge your Smart Student!
The correct answer is C.
Let “B” be the weight of the box and “C” be the weight of the candies. So:
B + C = 12
After \(\frac{2}{3}\) of the candies are eaten, the box and the remaining candies weigh 5 pounds. So,
B + \(\frac{1}{3}\) C = 5
Solve the system of two equations:
B + C = 12 → B = 12 – C
B + \(\frac{1}{3}\) C = 5 → 12 – C + \(\frac{1}{3}\) C = 5 → 12 – \(\frac{2}{3}\) C = 5 → C = 10.5
B = 12 – C → B = 12 – 10.5 = 1.5
The weight of the box is 1.5 pounds.The Best Books to Ace Algebra
Original price was: $27.99.$17.99Current price is: $17.99.
Related to This Article
More math articles
- Best Tablet For Math Note Taking
- 5th Grade KAP Math Worksheets: FREE & Printable
- Top Math Websites for Online Classes
- How to Use Models to Place Decimal Numbers in Order
- Decimals Unfolded: How to Switch Between Standard and Expanded Forms
- FREE 8th Grade NYSE Math Practice Test
- Customary Unit Conversions Involving Mixed Numbers and Fractions
- Full-Length ACT Math Practice Test
- Geometry Made Easy: Tips and Strategies for Success
- The Ultimate NM-MSSA Algebra 1 Course (+FREE Worksheets)
What people say about "Geometry Puzzle – Challenge 71 - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.