Algebra Puzzle – Challenge 55
Algebra Puzzle - Challenge 55 is a multiple-choice math challenge from Effortless Math. Read the problem, choose from the answer options below, then open the solution to see the full step-by-step working and check your reasoning against it.
Who can solve this great math puzzle? This is for smart people who love teasing their brains with math challenges!
Challenge:
Jason’s age is (frac{5}{8}) of Alice’s age now. In ten years, the sum of Jason’s and Alice’s age will be 72. How old will Alice be in 5 years?
A- 20
B- 30
C- 32
D- 37
E- 42
The Absolute Best Book to Challenge Your Smart Student!
The correct answer is D.
Let J be the Jason’s age and A be the Alice’s age. Then:
J =( frac{5}{8}) A
In 10 years: (J + 10) + (A + 10) = 72
Replace J with its value in the first equation:
Then: ((frac{5}{8} A + 10) + (A + 10) = 72 →1 frac{5}{8} A = 52 → A = 32)
In 5 years, Alice will be 37. (32 + 5 = 37)The Absolute Best Books to Ace Algebra
Related to This Article
More math articles
- Free Grade 8 English Worksheets for Florida Students
- The Ultimate 7th Grade SC Ready Math Course (+FREE Worksheets)
- Top 10 Tips to Overcome ACCUPLACER Math Anxiety
- Free Grade 3 English Worksheets for Wisconsin Students
- Top 10 Tips to Overcome AFOQT Math Anxiety
- Vector-Valued Functions: Fundamentals and Applications
- The Best Grade 5 Math Book for Mississippi Students
- Absentee and mail voting
- Compute comparative advantage
- Campaign-finance regulation












What people say about "Algebra Puzzle: Challenge 55"?
No one replied yet.